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Which Line Segment Of A Triangle Do You Draw To Find The Centroid Of A Triangle

Centroid of a Triangle

This page shows how to construct the centroid of a triangle with compass and straightedge or ruler. The centroid of a triangle is the point where its medians intersect. It works past amalgam the perpendicular bisectors of whatever two sides to observe their midpoints. And so the medians are drawn, which intersect at the centroid. This construction assumes you are already familiar with Amalgam the Perpendicular Bisector of a Line Segment.

Printable step-by-step instructions

The above animation is available as a printable step-by-pace pedagogy sheet, which can be used for making handouts or when a computer is not available.

Proof

The epitome below is the final drawing from the above animation.

Argument Reason
1 S is the midpoint of PQ S was found by constructing the perpendicular bisector of PQ. Meet Constructing the perpendicular bisector of a segment for the method and proof
2 RS is a median of the triangle PQR A median is a line from a vertex to the midpoint of the opposite side. Meet Median of a triangle.
three Similarly, PT is a median of the triangle PQR Every bit in (1), (ii).
iv C is the centroid of the triangle PQR The centroid of a triangle is the point where its medians intersect. See Centroid of a triangle.

- Q.E.D

Effort it yourself

Click hither for a printable worksheet containing centroid construction problems. When you get to the page, employ the browser print control to print as many as you wish. The printed output is not copyright.

Other constructions pages on this site

  • List of printable constructions worksheets

Lines

  • Introduction to constructions
  • Copy a line segment
  • Sum of n line segments
  • Difference of two line segments
  • Perpendicular bisector of a line segment
  • Perpendicular at a betoken on a line
  • Perpendicular from a line through a point
  • Perpendicular from endpoint of a ray
  • Separate a segment into north equal parts
  • Parallel line through a point (angle copy)
  • Parallel line through a point (rhomb)
  • Parallel line through a signal (translation)

Angles

  • Bisecting an bending
  • Copy an bending
  • Construct a 30° bending
  • Construct a 45° bending
  • Construct a 60° angle
  • Construct a xc° angle (correct angle)
  • Sum of northward angles
  • Deviation of two angles
  • Supplementary bending
  • Complementary angle
  • Amalgam  75°  105°  120°  135°  150° angles and more than

Triangles

  • Copy a triangle
  • Isosceles triangle, given base and side
  • Isosceles triangle, given base and altitude
  • Isosceles triangle, given leg and apex angle
  • Equilateral triangle
  • 30-sixty-90 triangle, given the hypotenuse
  • Triangle, given 3 sides (sss)
  • Triangle, given i side and adjacent angles (asa)
  • Triangle, given ii angles and non-included side (aas)
  • Triangle, given 2 sides and included bending (sas)
  • Triangle medians
  • Triangle midsegment
  • Triangle altitude
  • Triangle distance (outside instance)

Correct triangles

  • Right Triangle, given i leg and hypotenuse (HL)
  • Right Triangle, given both legs (LL)
  • Correct Triangle, given hypotenuse and ane angle (HA)
  • Correct Triangle, given ane leg and one angle (LA)

Triangle Centers

  • Triangle incenter
  • Triangle circumcenter
  • Triangle orthocenter
  • Triangle centroid

Circles, Arcs and Ellipses

  • Finding the center of a circle
  • Circle given 3 points
  • Tangent at a bespeak on the circumvolve
  • Tangents through an external point
  • Tangents to two circles (external)
  • Tangents to two circles (internal)
  • Incircle of a triangle
  • Focus points of a given ellipse
  • Circumcircle of a triangle

Polygons

  • Square given one side
  • Square inscribed in a circle
  • Hexagon given 1 side
  • Hexagon inscribed in a given circumvolve
  • Pentagon inscribed in a given circle

Non-Euclidean constructions

  • Construct an ellipse with string and pins
  • Find the eye of a circle with any correct-angled object

Source: https://www.mathopenref.com/constcentroid.html

Posted by: richardswhishour.blogspot.com

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